PCC GROUP RESEARCHES
PCC group
ask me to show some statistical formula to their research and some of them are theoretical
so I opted to have some research review on some of their formula and the
formula are as follows mean, percentage, and the one way anova or one way
classification of anova . I learned from
the group of students of PCC they are a critical thinker, which is great, or
maybe they are anxious and worried about their oral defense and they needed to
be precise and accurate because the panels are from the elite.
First is the percentage n/N x 100 where n is the sample and
N is the total number of sample for example
Frequency
|
Percent
|
||
Male
|
52
|
35.6
|
|
Female
|
94
|
64.4
|
|
Total
|
146
|
100.0
|
For male n = 52 N= 146 so percentage is (52/146) * 100= 35.6
Now for
the mean of grouped data: Ug = however, the data used in the study of the PCC
students is ungrouped mean, which the formula is as follows:
For
example
Factors
|
Sum
|
Mean
|
Overpopulation
|
295.00/n
|
2.0205
|
Low Demand
|
486.00/n
|
3.3288
|
Termination
|
487.00/n
|
3.3356
|
Low Salary
|
507.00/n
|
3.4726
|
Unable to
Pass
|
559.00/n
|
3.8288
|
Heath
Hazard
|
721.00/n
|
4.9384
|
Example
let fi= 4 or you have 4 total sample
Moreover,
their perception tabled as follows
overpopulation
|
Low demand
|
termination
|
Low salary
|
Unable to pass
|
Health hazard
|
|
Student 1
|
1
|
2
|
3
|
5
|
4
|
6
|
Student 2
|
2
|
6
|
5
|
1
|
3
|
2
|
Student 3
|
6
|
5
|
4
|
3
|
2
|
1
|
Student 4
|
1
|
2
|
3
|
4
|
5
|
6
|
sum
|
10
|
15
|
15
|
13
|
14
|
15
|
mean
|
10/4
|
15/4
|
15/4
|
13/4
|
14/4
|
15/4
|
The analysis of variance
is an extension or generalization of the difference of means test. The
technique is used several means, however the test itself involve directly with
the variance rather than means and standard errors.
The one-way anova classification,
two component of variation are estimated for example the data PCC nursing
students in identifying if those living or not living with their family have
significant difference in terms of the indicators of eating habit. The data is
as follows:
Indicator
|
Living in the Family
|
WT Mean
|
F.
|
P
|
1. Plans daily activity
|
Yes
No
|
3.3
3.28
|
.013
|
.908 ns
|
2. Finds time to cook nutritious
food
|
Yes
No
|
3.44
3.21
|
1.568
|
.212 ns
|
3. Allocates Time to buy Food
|
Yes
No
|
3.39
3.33
|
.070
|
.792 ns
|
4. Share Household Chores with house
mates
|
Yes
No
|
3.60
3.51
|
0.201
|
.654 ns
|
5. Acquiring skills in Preparing
and Cooking
|
Yes
No
|
3.50
3.51
|
.005
|
.941 ns
|
The
variations are the indicator of the students and the other variation is if the
student is living or living away with his or her family. Then the ratio of these
estimates computed. If the null hypothesis is correct then this ratio approaches
unity but is the difference is entirely different, and then the ratio tends to
be large. The ratio of the two variances denotes F knows a test statistics as
the F-test.
The
estimation of sum of squares is as follows
a.)
Correction
factor (CF) CF= (1/n)(x..)2
b.)
Total
sum of Squares (TSS) TSS= ƸƸXij2 – CF
c.)
Treatment
Sum of Squares (TRSS) TRSS= Ƹ(Xi2 /ni) – CF or Between
Group Sum of Squares
d.)
Within group sum of squares ESS = TSS – TRSS
or Within Group Some of Squares
e.)
F = Mean Square Between group/Mean
Square Within Group from the output or
F
= ( TRSS/(t-1)) / ( ESS/ (n-t)
ANOVA output
Sum of
Squares
|
df
|
Mean
Square
|
F
|
Sig.
|
||
Plans daily activity
|
Between Groups
|
.016
|
1
|
.016
|
.013
|
.908
|
Within Groups |
192.591
|
156
|
1.235
|
|||
Total |
192.608
|
157
|
So let us take the test if there
is a significance of those living and living away with their family The TSS or
Total sum of squares is 192.61
TRSS or Between Group Sum of Squares = .016
ESS
or Within Group Some of Squares = 192.591
For
for computation of the F value is
a.)
F = Mean Square Between group/Mean
Square Within Group from the output or
F = (TRSS/ (t-1)) / (ESS/ (n-t) =
.016/1.235 = .013
Take note in your study we set the
value of critical region is .05 and the
program automatically compute the significant value or the P value thus any value
within or lower than .05 is a significant one and any value higher than .05 is
a not significant.
The Pvalue or calculated probability is the estimated probability of rejecting the null hypothesis (H0)
of a study question when that hypothesis is true.
As a rule in the ideal world, we would be able to define a
"perfectly" random sample, the most appropriate test and one
definitive conclusion. We simply cannot. What we can do is try to optimize all
stages of our research to minimize sources of uncertainty. When presenting P
values some groups find it helpful to use the asterisk rating system as well as
quoting the P value:
P < 0.05 *P < 0.01 **
P < 0.001
Most authors refer to statistically significant as P < 0.05 and statistically highly significant as P < 0.001 (less than one in a thousand chance of being wrong). So in your research we do same.
The asterisk system avoids the woolly term "significant". Please note, however, that many statisticians do not like the asterisk rating system when it used without showing P values. As a rule of thumb, if you can quote an exact P value then do. You might also want to refer to a quoted exact P value as an asterisk in text narrative or tables of contrasts elsewhere in a report.
Mind you computing the F test
manually would take no less than 3 session of regular lecture so the
computation are being deducted and the results are being obtained automatically.
The data are being done from statistical software, which is design to compute
the needed test.
For the
other group who have significant difference per region and region 3 is the
significant one and the post hoc test used is Fisher LSD. The Fisher LSD test stands for the Least
Significant Difference test (rather than what you might have guessed). The LSD test is simply the rationale that if
an omnibus test is conducted and is significant, the null hypothesis is incorrect.
(If the omnibus test is non significant, no post hoc tests are conducted.) The
reasoning is based on the assumption that if the null hypothesis is incorrect,
as indicated by a significant omnibus F-test, Type I errors are not really
possible (or less likely), because they only occur when the null is true. So,
by conducting an omnibus test first, one is screening out group differences
that exist due to sampling error, and thus reducing the likelihood that a Type
I error is present among the means.
Fishers LSD test has been criticized for not sufficiently controlling
for Type I error.
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