IQ
|
TEST SCORE
|
X1*X2
|
IQ2
|
TS2
|
106
|
16
|
1696
|
11236
|
256
|
118
|
21
|
2478
|
13924
|
441
|
80
|
10
|
800
|
6400
|
100
|
120
|
25
|
3000
|
14400
|
625
|
117
|
16
|
1872
|
13689
|
256
|
94
|
11
|
1034
|
8836
|
121
|
106
|
6
|
636
|
11236
|
36
|
119
|
32
|
3808
|
14161
|
1024
|
107
|
20
|
2140
|
11449
|
400
|
128
|
15
|
1920
|
16384
|
225
|
122
|
26
|
3172
|
14884
|
676
|
116
|
18
|
2088
|
13456
|
324
|
1333
|
216
|
24644
|
150055
|
4484
|
Test 2 Self test I
rxy= 1
Rxy =
12(24644)-[( 1333)(216)]/ ⁄(12*150055)-(1333)2]
[(12*4484)-(216)2]
= 0.598215
The above result
indicates tha there is a moderate direct
relationship between I Q and methemathical test Score .
This implies hat as IQ increases Mathematical moderately would increase also.
B1 - =
24644-(1333)(216)____ =
0.328
150055- (1333)2/12
Bo =
Mean Y – bi meanX = 18-
(0.328)(111.0833) = - 18.4499
The regression equation
is
Mathematical Test
Score = -18.4499 + 0.328131 IQ
Se = Sy = 7.36 x .80134 = 5.897
Approximately
68% of the samples will have a actual score that lie within the Se of their
predicted scores YỸ +/- 5.897 = 18 +/- (5.897) . in other words 68% have scores
within the range 12.103 to 23.897. Like wise, approximately 95% of the samples
will have the actual scores that lie within two Se’s their predicted scores;18
+/- 11.794 or 6.206 to 29.794.
The regression equation
is
Mathematical = -18.4499 +
0.328131 IQ
S = 6.18640 R-Sq = 35.8 % R-Sq(adj) = 29.4 %
Analysis of Variance
Source DF SS MS F
P
Regression 1
213.285 213.285 5.57295
0.040
Error 10 382.715
38.271
Total 11 596.000
SELF Test 1
No 1
sample
|
Gen Ave
|
Applitude
|
X1*X2
|
x12
|
x22
|
1
|
93
|
94
|
8742
|
8649
|
8836
|
2
|
88
|
82
|
7216
|
7744
|
6724
|
3
|
87
|
90
|
7830
|
7569
|
8100
|
4
|
89
|
87
|
7743
|
7921
|
7569
|
5
|
84
|
86
|
7224
|
7056
|
7396
|
6
|
82
|
85
|
6970
|
6724
|
7225
|
7
|
80
|
76
|
6080
|
6400
|
5776
|
8
|
91
|
86
|
7826
|
8281
|
7396
|
9
|
87
|
80
|
6960
|
7569
|
6400
|
10
|
86
|
81
|
6966
|
7396
|
6561
|
11
|
81
|
84
|
6804
|
6561
|
7056
|
12
|
88
|
80
|
7040
|
7744
|
6400
|
13
|
90
|
85
|
7650
|
8100
|
7225
|
14
|
82
|
84
|
6888
|
6724
|
7056
|
15
|
83
|
88
|
7304
|
6889
|
7744
|
total
|
1291
|
1268
|
109243
|
111327
|
107464
|
pearson
product-moment coefficient of correlation
rxy= 1
Rxy =
15(109243)-[( 1291)(1268)]/ ⁄(15*111327)-(1291)2]
[(15*107464)-(1268)2]
= 0.453769
The above result
indicates tha there is a moderate direct
relationship between General Average and
Applitude test Score . This implies hat as General Average increases Applitude
test score moderately would increase also.
Pearson correlation of C5
and C6 = 0.454
P-Value = 0.089
To madam Molina
a.X1 sex and X2 eduactional attainment
correlation used: Phi Coefficient
a
|
4
|
bc
|
6
|
|
b
|
3
|
ad
|
24
|
|
c
|
2
|
a+c
|
6
|
|
d
|
6
|
b+d
|
9
|
|
a+b
|
7
|
|||
c+d
|
8
|
.rq =(6)-(24)
__________ = -
0.32733
√3024
The relationship between sex and and educational attainment
have definite but small negative correlation.
b. X1 sex and X3 type of employement
correlation used: Phi Coefficient
a
|
4
|
bc
|
16
|
|
b
|
4
|
ad
|
12
|
|
c
|
4
|
a+c
|
8
|
|
d
|
3
|
b+d
|
7
|
|
a+b
|
8
|
|||
c+d
|
7
|
rq=(16)-(12)
__________ = 0.0714
√3136
The result suggest that there is slight
relationship between sex and type of employement
c. X2
Educational attainment and x3 Type of employement
correlation used: Phi Coefficient
a
|
4
|
bc
|
12
|
|
b
|
4
|
ad
|
16
|
|
c
|
3
|
a+c
|
7
|
|
d
|
4
|
b+d
|
8
|
|
a+b
|
8
|
|||
c+d
|
7
|
Rq= (12)-(16)
__________ = -0.07143
√3136
The result suggest that there is slight negative relationship between type of employement and
educational attainement
d. X2 educational attainment and x4 Rank in
laedership qualities
correlation used: Rank biseral coefficient
sum with masters degree= 53 mean = 6.625
sum with out masters = 67 mean= 9.571
N= 15
Rs = 2/15 (6.625-9.571)
= -0.3928
The realtionship between educational attainment and
leadearship qualitiies have slight but not definite or can be also considered
as aweak relationship.
e. X2 educational attainment
and x6 verbal applitude
correlation used: point biseral coefficient
mean w1= 86.5 N1=
8
mean x6= 84.6 No=
7
SD of x6= 6.684 N
= 15
.rpb = 86.5-84.6/6.684
[√8(15)/7(14)
= 0.314
A slight but not definite relationship is being considered
in terms of the relationship between eduactional attainment and verbal
applitude
f. x4 rank in leadership qualities and x5 rank in creativity
test
correlation used: spearman rho correlation coefficient
x4
|
x5
|
X4-x5
|
(x4-x5)2
|
|||
9
|
6
|
3
|
9
|
696
|
||
13
|
7
|
-4
|
16
|
225
|
||
1
|
5
|
-4
|
16
|
3360
|
||
12
|
14
|
-2
|
4
|
0.207143
|
||
7
|
10
|
-3
|
9
|
0.792857
|
||
8
|
8
|
0
|
0
|
|||
2
|
4
|
-2
|
4
|
|||
11
|
13
|
-2
|
4
|
|||
15
|
11
|
4
|
16
|
|||
10
|
9
|
1
|
1
|
|||
4
|
1
|
3
|
9
|
|||
5
|
3
|
2
|
4
|
|||
14
|
12
|
2
|
4
|
|||
13
|
15
|
-2
|
4
|
|||
6
|
2
|
4
|
16
|
|||
116
|
Rs =
1- 6 Ƹ(116)/15(152-1)
= 0.793
The
relationship between the two ranks are substantial we can say as their
leadership increase their creativity also increase
G X4 rank in leadership qualities and X6 verbal applitude
correlation used: spearman rho correlation coefficient
x4
|
x6
|
x6 ranked
|
x-y
|
(x-y)2
|
|
9
|
90
|
12.5
|
-3.5
|
12.25
|
5475
|
3
|
88
|
10
|
-7
|
49
|
225
|
1
|
85
|
7
|
-6
|
36
|
3360
|
12
|
86
|
8
|
4
|
16
|
1.629464
|
7
|
82
|
5
|
2
|
4
|
-0.62946
|
8
|
90
|
12.5
|
-4.5
|
20.25
|
|
2
|
89
|
11
|
-9
|
81
|
|
11
|
83
|
6
|
5
|
25
|
|
15
|
80
|
4
|
11
|
121
|
|
10
|
78
|
3
|
7
|
49
|
|
4
|
95
|
15
|
-11
|
121
|
|
5
|
91
|
14
|
-9
|
81
|
|
14
|
75
|
2
|
12
|
144
|
|
13
|
70
|
1
|
12
|
144
|
|
6
|
87
|
9
|
-3
|
9
|
|
912.5
|
Rs =
1- 6 Ƹ(912.5)/15(152-1)
= -0.629
The
relationship between the two ranks are substantial and inversely proportional
as their leadership skill goes up their applitude substantialy goes down.
h. X5 rank in creativity and
X6 verbal applitude
correlation used: spearman rho correlation coefficient
x5
|
x6
|
Rankedx6
|
x-y
|
(x-y)2
|
|
6
|
90
|
12.5
|
-6.5
|
42.25
|
5889
|
7
|
88
|
10
|
-3
|
9
|
225
|
5
|
85
|
7
|
-2
|
4
|
3360
|
14
|
86
|
8
|
6
|
36
|
1.752679
|
10
|
82
|
5
|
5
|
25
|
-0.75268
|
8
|
90
|
12.5
|
-4.5
|
20.25
|
|
4
|
89
|
11
|
-7
|
49
|
|
13
|
83
|
6
|
7
|
49
|
|
11
|
80
|
4
|
7
|
49
|
|
9
|
78
|
3
|
6
|
36
|
|
1
|
95
|
15
|
-14
|
196
|
|
3
|
91
|
14
|
-11
|
121
|
|
12
|
75
|
2
|
10
|
100
|
|
15
|
70
|
1
|
14
|
196
|
|
2
|
87
|
9
|
-7
|
49
|
|
981.5
|
Rs =
1- 6 Ƹ(981.5)/15(152-1)
= -0.7526
The
realtionship between rank increativity and verbal applitude are subtantially
inversely proportional as the creatuvity increase the applitude decreases
.i X5 rank in creativity and
X7 numerical proficiency
correlation used: spearman rho correlation coefficient
x5
|
X7
|
ranked
|
x-y
|
(x-y)2
|
|
6
|
89
|
13
|
-7
|
49
|
4773
|
7
|
87
|
11
|
-4
|
16
|
225
|
5
|
83
|
7.5
|
-2.5
|
6.25
|
3360
|
14
|
85
|
9.5
|
4.5
|
20.25
|
1.420536
|
10
|
90
|
14
|
-4
|
16
|
-0.42054
|
8
|
85
|
9.5
|
-1.5
|
2.25
|
|
4
|
81
|
5.5
|
-1.5
|
2.25
|
|
13
|
79
|
4
|
9
|
81
|
|
11
|
75
|
1
|
10
|
100
|
|
9
|
76
|
2
|
7
|
49
|
|
1
|
93
|
15
|
-14
|
196
|
|
3
|
88
|
12
|
-9
|
81
|
|
12
|
83
|
7.5
|
4.5
|
20.25
|
|
15
|
77
|
3
|
12
|
144
|
|
2
|
81
|
5.5
|
-3.5
|
12.25
|
|
795.5
|
Rs =
1- 6 Ƹ(795.5)/15(152-1)
= -0.420
The
corellation of ranked in creativity and numerical proficientcy are in moderate
category somehow creativity have effect on numerical proficiency indirectly or
inversly proportional as creativity increase numerical proficiency moderately
decrease.
j. X6 verbal applitude and X7 numerical profficiency
pearson
product-moment coefficient of correlation
x6
|
x7
|
x6*x7
|
x62
|
x72
|
90
|
89
|
8010
|
8100
|
7921
|
88
|
87
|
7656
|
7744
|
7569
|
85
|
83
|
7055
|
7225
|
6889
|
86
|
85
|
7310
|
7396
|
7225
|
82
|
90
|
7380
|
6724
|
8100
|
90
|
85
|
7650
|
8100
|
7225
|
89
|
81
|
7209
|
7921
|
6561
|
83
|
79
|
6557
|
6889
|
6241
|
80
|
75
|
6000
|
6400
|
5625
|
78
|
76
|
5928
|
6084
|
5776
|
95
|
93
|
8835
|
9025
|
8649
|
91
|
88
|
8008
|
8281
|
7744
|
75
|
83
|
6225
|
5625
|
6889
|
70
|
77
|
5390
|
4900
|
5929
|
87
|
81
|
7047
|
7569
|
6561
|
1269
|
1252
|
106260
|
107983
|
104904
|
Rxy =
15(106260)-[( 1269)( 1252)]/ √[(15*107983)-(1269)2]
[(15*104904)-(1252)2]
= 0.678116
The above result
indicates tha there is a substantial direct relationship between . X6 verbal
applitude and X7 numerical profficiency. This implies hat as verbal applitude
increases numerical proficiency substantially increase also.
Analysis of Variance
Source DF
SS MS F
P
Factor 2
186.2 93.1 3.37
0.049
Error 27
745.8 27.6
Total 29
932.0
Individual
95% CIs For Mean
Based on Pooled StDev
Level N
Mean StDev -+---------+---------+---------+-----
C9 10
24.900 7.078 (---------*---------)
C10 10
26.500 3.923 (---------*--------)
C11 10
20.600 4.169
(---------*---------)
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